我有一个数组包含玩家的名字,我想按照数组的顺序显示每个问题中玩家的名字,例如arrnames['mark','john','jay'],我想和问题1的mark,问题2的john一起显示。
这是我正在尝试的,但我只得到数组中的最后一个值,我如何修复它?
const names = [];
var counter = 0;
const limit = 4 * localStorage.getItem('playersNum');
nextBtn.addEventListener('click', function() {
if(counter < limit) {
// Display player's name and ask question
for (let i = 0; i < names.length; i++) {
const playerName = document.getElementById('card-title');
playerName.innerText = names[i];
console.log(names);
}
const h6 = document.getElementById('h6');
h6.innerHTML = "Question " + (counter + 1);
nextBtn.innerHTML = "Next";
// Randomely pick a question from the array
randomItem = questions[Math.floor(Math.random()*questions.length)];
random = document.getElementById('questions');
random.innerText = randomItem;
counter++;
} else {
alert('No more questions !')
}
});
改变
// Display player's name and ask question
for (let i = 0; i < names.length; i++) {
const playerName = document.getElementById('card-title');
playerName.innerText = names[i];
console.log(names);
}
至
const playerName = document.getElementById('card-title');
playerName.innerText = names[counter];
为什么,因为它循环所有名称,而不管counter
的当前值如何,所以您只能看到姓。