提问者:小点点

求和对象数组中具有相同对象属性b的javascript对象属性a值


如何处理对象的javascript数组,例如:

my objArr = [
{key:Mon Sep 23 2013 00:00:00 GMT-0400, val:42},
{key:Mon Sep 24 2013 00:00:00 GMT-0400, val:78},
{key:Mon Sep 25 2013 00:00:00 GMT-0400, val:23},
{key:Mon Sep 23 2013 00:00:00 GMT-0400, val:54}]

并通过求和这些值合并重复的键。为了得到这样的东西:

my reducedObjArr = [
{key:Mon Sep 23 2013 00:00:00 GMT-0400, val:96},
{key:Mon Sep 24 2013 00:00:00 GMT-0400, val:78},
{key:Mon Sep 25 2013 00:00:00 GMT-0400, val:23}]

我尝试过迭代并添加到一个新数组中,但这没有起到作用:

var reducedObjArr = [];
var item = null, key = null;
for(var i=0; i<objArr.length; i++) {
   item=objArr[i];
   key = Object.keys(item)[0];
   item=item[key];

   if(!result[key]){
       result[key] = item;
   }else{
       result[key] += item;}
   }a

共2个答案

匿名用户

应该将未找到的每个对象分配给具有.key属性的结果。

如果找到它,那么您需要添加它的.val

var temp = {};
var obj = null;
for(var i=0; i < objArr.length; i++) {
   obj=objArr[i];

   if(!temp[obj.key]) {
       temp[obj.key] = obj;
   } else {
       temp[obj.key].val += obj.val;
   }
}
var result = [];
for (var prop in temp)
    result.push(temp[prop]);

另外,部分问题是您重用item变量来引用.key的值,因此丢失了对对象的引用。

匿名用户

您可以直接使用map和reduce,而不是使用for循环和推送值:

null

let objArr = [
  {key: 'Mon Sep 23 2013 00:00:00 GMT-0400', val: 42},
  {key: 'Mon Sep 24 2013 00:00:00 GMT-0400', val: 78},
  {key: 'Mon Sep 25 2013 00:00:00 GMT-0400', val: 23},
  {key: 'Mon Sep 23 2013 00:00:00 GMT-0400', val: 54}
];

// first, convert data into a Map with reduce
let counts = objArr.reduce((prev, curr) => {
  let count = prev.get(curr.key) || 0;
  prev.set(curr.key, curr.val + count);
  return prev;
}, new Map());

// then, map your counts object back to an array
let reducedObjArr = [...counts].map(([key, value]) => {
  return {key, value}
})

console.log(reducedObjArr);