好吧，我已经在这方面工作了两天了--我的代码有点草率和混乱，但我已经翻阅了数百个问题，网站等等，寻找一个答案，或者只是一个我理解的解释；不幸的是，我的尝试仍然没有成功。

我正在PHP/HTML中构建一个“问答”游戏--该网站引用了一个数据库，特别是一个标有“答案”的列表，其中包含以下信息：

 - ID: Auto-Increment
 - Question: Varchar
 - Answer: Varchar
 - Comment: Varchar

现在，对于站点的一点信息--一旦用户登录，他/她就可以“玩”游戏；游戏只是一个HTML表单，上面显示一个随机的“答案表”问题。该表单有4个用户输入，但只需要两个。让我进入代码的细节，然后我会问我的问题：

我的index.php页面（包含游戏表单）当前为：

<?php # index.php
 session_start();
   //check session first
   if (!isset($_SESSION['email'])){
     include ('../includes/header.php');
   }else
         {
   session_start();
      include ('../includes/header.php');
      require_once ('../../mysql_connect.php');
      $query = "SELECT * FROM answers ORDER BY RAND() LIMIT 1"; 
      $result = @mysql_query ($query);
      $num = mysql_num_rows($result);
         if ($num > 0) { // If it ran OK, display all the records.
            while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {        
 ?>

 <div class="newGame">
    <h2>Are you a Question Master?<hr /></h2>
    <h3 style="color:#000">Find Out Now!</h3>
 </div>
 <br />

 <div class="newGameContain">
    <form action="gameSubmit.php" method="post" autocomplete="off">
       <h2><? echo $row["Question"]."<hr />"; ?></h2>
       <h3>Enter Player Answers</h3>
           <p><input type="text" placeholder="Player 1" name="player1" value="<? echo $_POST['player1']; ?>" /> <input type="text" placeholder="Player 2" name="player2" value="<? echo $_POST['player2']; ?>" /></p>
           <p><input type="text" placeholder="Player 3" name="player3" value="<? echo $_POST['player3']; ?>" /> <input type="text" placeholder="Player 4" name="player4" value="<? echo $_POST['player4']; ?>" /></p>
           <p><input type="submit" class="submitButton" /> <input type="reset" class="resetButton" value="Reset" /> </p>
           <input type="hidden" name="ID" value="<?php echo $row["ID"]; ?>" />
           <input type="hidden" name"Answer" value="<?php echo $row['Answer']; ?>" />
           <input type="hidden" name="submitted" value="TRUE" />
    </form>
    <p></p>
  </div>
  <br />


 <?php
    } //end while statement
} //end if statement
mysql_close();
//include the footer
include ("../includes/footer.php");
 }
 ?>

那么我的gameSubmit.php页面（表单动作）看起来是这样的--我只会给出一个快照，而不是全部：

 <?php # index.php
 session_start();
 //check session first
 if (!isset($_SESSION['email'])){
    include ('../includes/header.php');
 }else
     {
 session_start();
 include ('../includes/header.php');
 require_once ('../../mysql_connect.php');
$query = "SELECT * FROM answers ORDER BY RAND() LIMIT 1"; 
$result = @mysql_query ($query);
$num = mysql_num_rows($result);
if ($num > 0) { // If it ran OK, display all the records.
    while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {        
 ?>

 <? if (isset($_POST['submitted'])){

      $correct1Msg = "<div class='correct1Msg'><p style='color:#000;font-family:Arial, Helvetica, sans-serif;'>Player 1 entered the <span id='answerUnder'>correct answer</span>.</p></div><p></p>";
      $correct2Msg = "<div class='correct2Msg'><p style='color:#000;font-family:Arial, Helvetica, sans-serif;'>Player 2 entered the <span id='answerUnder'>correct answer</span>.</p></div><p></p>";

      $incorrect1Msg = "<div class='incorrect1Msg'><p style='color:#F00;font-family:Arial, Helvetica, sans-serif;'>Player 1 entered the <span id='answerUnder'>incorrect answer</span>.</p></div><p></p>";
      $incorrect2Msg = "<div class='incorrect2Msg'><p style='color:#F00;font-family:Arial, Helvetica, sans-serif;'>Player 2 entered the <span id='answerUnder'>incorrect answer</span>.</p></div><p></p>";

          $player1Answer = $_POST['player1'];
          $player2Answer = $_POST['player2'];
          $player3Answer = $_POST['player3'];
          $player4Answer = $_POST['player4'];

          $questionID = $row['ID'];

    if ($questionID == "1" && $player1Answer != "Red"){
        echo $incorrect1Msg;
    }elseif ($questionID == "2" && $player1Answer != "4"){
        echo $incorrect1Msg;
    }else {
        echo $correct1Msg;
    }

    if ($questionID == "1" && $player2Answer == "Red"){
        echo $correct2Msg;
    }elseif ($questionID == "2" && $player2Answer == "4"){
        echo $correct2Msg;
    }else{
        echo $incorrect2Msg;
    }
 }
 ?>

 <?php
           } //end while statement
      } //end if statement
      mysql_close();
      //include the footer
      include ("../includes/footer.php");
 }
 ?>

请注意，gameSubmit.php页面也有相同的消息和if...elseif...player3Answer和Player4Answer的语句。

所以我的问题是...

如果用户登录并打开index.php页面，会提示他/她“echo$row[”question“]”（这是一个使用$query=“select*from answers ORDER BY RAND（）LIMIT 1”从MySQL数据库中提取的问题；-然后用户继续在每个玩家各自的文本输入中输入一个答案。一旦用户单击submit按钮，表单重定向到gameSubmit.php-一旦加载，If(isset($_post['submited'])){启动并交叉检查每个用户的答案并显示各自的消息。

目前，我的表单重定向到gameSubmit.php，但是，它没有引用前面的问题来获得正确答案--因此，在“评分”答案时出现相同的答案完全是它的运气。

为了在表单操作页上实现输入验证，我需要做什么/需要更正什么？

再一次，我只是想随机检索一个问题，并在提交时用正确的答案检查输入的答案--我也希望我的代码能够检索正确的答案，而不是我必须键入每个答案，这样，如果添加了一个记录，我就不必更新代码。

感谢您的时间和帮助，非常感谢！（今天是决赛周，我的压力太大了。）

• Rockmandew