因此,我试图重新生成这个一维动态数组,但无法修复此错误:写入'NEW_ARR'时缓冲区溢出:可写大小为'NEWLENGTH*1'字节,但可能会写入2个字节
void regrow(char *&arr, int &length,int newLength) //Funcion to regrow an array
{
char* new_arr = new char[newLength];
for (int index = 0; index < length; index++)
{
new_arr[index] = arr[index]; //**Error occurs here**
}
length = newLength;
delete[] arr;
arr = new_arr;
}
缓冲区溢出错误通常检测您是否尝试在未分配的空间中写入,这可能是由于newlength
小于length
本身造成的,这可以通过if-return检查来避免:
#include <iostream>
void regrow(char *&arr, int &length,int newLength) //Funcion to regrow an array
{
if(length >= newLength){ //Check for correct input
return;
}else{
char* new_arr = new char[newLength];
for (int index = 0; index < length; index++)
{
new_arr[index] = arr[index]; //**Error occurs here**
}
length = newLength;
delete[] arr;
arr = new_arr;
}
}
int main()
{
int a = 5;
int b = 8;
char*array = new char[a]{'C','B','a','d','f'};
regrow(array,a,b);
for(int i = 0; i < a; ++i){
std::cout << array[i] << std::endl;
}
return 0;
}